Logan County | |
---|---|
Coordinates: 38°54′N 101°08′W / 38.900°N 101.133°W | |
Country | United States |
State | Kansas |
Founded | February 24, 1887 |
Named for | John A. Logan |
Seat | Oakley |
Largest city | Oakley |
Area | |
• Total | 1,073 sq mi (2,780 km2) |
• Land | 1,073 sq mi (2,780 km2) |
• Water | 0.1 sq mi (0.3 km2) 0.01% |
Population | |
• Total | 2,762 |
• Density | 2.6/sq mi (1.0/km2) |
Time zone | UTC−6 (Central) |
• Summer (DST) | UTC−5 (CDT) |
Congressional district | 1st |
Website | discoveroakley.com |
Logan County (standard abbreviation: LG) is a county in the U.S. state of Kansas. In 2020, 2,762 people lived there.[1] The county seat is Oakley. Oakley is also the biggest city in Logan County.[2] The county was named after Gen. John A. Logan.[3]
One of the county's most unique features is a mile long stretch of Niobrara Formation rocks. The rocks reach 100 feet high. They are called "Little Jerusalem." It is related to the same geology that formed the Badlands National Park. The formation is mostly on private land. In 2016, the Nature Conservancy bought the land, and they say they will open the area to the public.[4]
In 1887, Logan County was created.
Logan County was first created in 1871 as St. John County. St. John was created from the area to the east of range 38 in what was then part of Wallace County. The Kansas State Legislature changed the name from St. John to Logan in 1885.[5]
The U.S. Census Bureau says that the county has a total area of 1,073 square miles (2,780 km2). Of that, 1,073 square miles (2,780 km2) is land and 0.1 square miles (0.26 km2) (0.01%) is water.[6]
Historical population | |||
---|---|---|---|
Census | Pop. | %± | |
1890 | 3,384 | — | |
1900 | 1,962 | −42.0% | |
1910 | 4,240 | 116.1% | |
1920 | 3,223 | −24.0% | |
1930 | 4,145 | 28.6% | |
1940 | 3,688 | −11.0% | |
1950 | 4,206 | 14.0% | |
1960 | 4,036 | −4.0% | |
1970 | 3,814 | −5.5% | |
1980 | 3,478 | −8.8% | |
1990 | 3,081 | −11.4% | |
2000 | 3,046 | −1.1% | |
2010 | 2,756 | −9.5% | |
2020 | 2,762 | 0.2% | |
U.S. Decennial Census[7] 1790-1960[8] 1900-1990[9] 1990-2000[10] 2010-2020[1] |
Year | Republican | Democratic | Third Parties |
---|---|---|---|
2020 | 85.7% 1,249 | 12.8% 186 | 1.6% 23 |
2016 | 83.2% 1,132 | 10.9% 149 | 5.9% 80 |
2012 | 83.4% 1,126 | 14.6% 197 | 2.0% 27 |
2008 | 82.4% 1,187 | 15.6% 225 | 1.9% 28 |
2004 | 82.4% 1,255 | 16.3% 248 | 1.3% 20 |
2000 | 77.9% 1,088 | 16.5% 231 | 5.6% 78 |
1996 | 73.5% 1,155 | 18.8% 296 | 7.7% 121 |
1992 | 53.0% 905 | 20.8% 355 | 26.3% 449 |
1988 | 64.4% 988 | 32.8% 503 | 2.9% 44 |
1984 | 77.0% 1,235 | 20.7% 331 | 2.3% 37 |
1980 | 72.9% 1,261 | 20.7% 358 | 6.4% 111 |
1976 | 56.4% 957 | 40.9% 694 | 2.7% 46 |
1972 | 70.0% 1,164 | 25.7% 428 | 4.3% 71 |
1968 | 63.8% 1,120 | 23.4% 411 | 12.8% 225 |
1964 | 49.8% 967 | 49.3% 957 | 0.9% 17 |
1960 | 65.2% 1,243 | 34.2% 651 | 0.6% 12 |
1956 | 72.6% 1,328 | 27.0% 493 | 0.4% 8 |
1952 | 80.0% 1,544 | 19.1% 369 | 0.9% 18 |
1948 | 63.7% 1,105 | 33.4% 579 | 2.9% 50 |
1944 | 72.9% 1,107 | 26.8% 406 | 0.3% 5 |
1940 | 66.8% 1,201 | 32.5% 584 | 0.7% 12 |
1936 | 51.2% 955 | 48.6% 908 | 0.2% 4 |
1932 | 44.3% 867 | 52.3% 1,025 | 3.4% 67 |
1928 | 71.6% 1,066 | 27.2% 405 | 1.1% 17 |
1924 | 63.9% 942 | 19.4% 286 | 16.8% 247 |
1920 | 68.5% 781 | 27.4% 312 | 4.1% 47 |
1916 | 42.1% 592 | 50.4% 709 | 7.6% 107 |
1912 | 20.2% 166 | 31.6% 259 | 48.2% 396[a] |
1908 | 59.3% 524 | 34.9% 308 | 5.8% 51 |
1904 | 71.8% 408 | 20.6% 117 | 7.6% 43 |
1900 | 60.5% 319 | 33.4% 176 | 6.1% 32 |
1896 | 60.4% 274 | 38.6% 175 | 1.1% 5 |
1892 | 58.1% 457 | 41.9% 329 | |
1888 | 65.8% 609 | 30.6% 283 | 3.6% 33 |
Logan County is very Republican. Only two Democrats have ever won the county in a Presidential election: Woodrow Wilson in 1916 and Franklin D. Roosevelt in 1932.